4k^2=-k+1

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Solution for 4k^2=-k+1 equation:



4k^2=-k+1
We move all terms to the left:
4k^2-(-k+1)=0
We add all the numbers together, and all the variables
4k^2-(-1k+1)=0
We get rid of parentheses
4k^2+1k-1=0
We add all the numbers together, and all the variables
4k^2+k-1=0
a = 4; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·4·(-1)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{17}}{2*4}=\frac{-1-\sqrt{17}}{8} $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{17}}{2*4}=\frac{-1+\sqrt{17}}{8} $

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